3.1218 \(\int \frac{1-2 x}{(2+3 x)^4 (3+5 x)^2} \, dx\)

Optimal. Leaf size=55 \[ -\frac{505}{3 x+2}-\frac{275}{5 x+3}-\frac{34}{(3 x+2)^2}-\frac{7}{3 (3 x+2)^3}+3350 \log (3 x+2)-3350 \log (5 x+3) \]

[Out]

-7/(3*(2 + 3*x)^3) - 34/(2 + 3*x)^2 - 505/(2 + 3*x) - 275/(3 + 5*x) + 3350*Log[2 + 3*x] - 3350*Log[3 + 5*x]

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Rubi [A]  time = 0.0251528, antiderivative size = 55, normalized size of antiderivative = 1., number of steps used = 2, number of rules used = 1, integrand size = 20, \(\frac{\text{number of rules}}{\text{integrand size}}\) = 0.05, Rules used = {77} \[ -\frac{505}{3 x+2}-\frac{275}{5 x+3}-\frac{34}{(3 x+2)^2}-\frac{7}{3 (3 x+2)^3}+3350 \log (3 x+2)-3350 \log (5 x+3) \]

Antiderivative was successfully verified.

[In]

Int[(1 - 2*x)/((2 + 3*x)^4*(3 + 5*x)^2),x]

[Out]

-7/(3*(2 + 3*x)^3) - 34/(2 + 3*x)^2 - 505/(2 + 3*x) - 275/(3 + 5*x) + 3350*Log[2 + 3*x] - 3350*Log[3 + 5*x]

Rule 77

Int[((a_.) + (b_.)*(x_))*((c_) + (d_.)*(x_))^(n_.)*((e_.) + (f_.)*(x_))^(p_.), x_Symbol] :> Int[ExpandIntegran
d[(a + b*x)*(c + d*x)^n*(e + f*x)^p, x], x] /; FreeQ[{a, b, c, d, e, f, n}, x] && NeQ[b*c - a*d, 0] && ((ILtQ[
n, 0] && ILtQ[p, 0]) || EqQ[p, 1] || (IGtQ[p, 0] && ( !IntegerQ[n] || LeQ[9*p + 5*(n + 2), 0] || GeQ[n + p + 1
, 0] || (GeQ[n + p + 2, 0] && RationalQ[a, b, c, d, e, f]))))

Rubi steps

\begin{align*} \int \frac{1-2 x}{(2+3 x)^4 (3+5 x)^2} \, dx &=\int \left (\frac{21}{(2+3 x)^4}+\frac{204}{(2+3 x)^3}+\frac{1515}{(2+3 x)^2}+\frac{10050}{2+3 x}+\frac{1375}{(3+5 x)^2}-\frac{16750}{3+5 x}\right ) \, dx\\ &=-\frac{7}{3 (2+3 x)^3}-\frac{34}{(2+3 x)^2}-\frac{505}{2+3 x}-\frac{275}{3+5 x}+3350 \log (2+3 x)-3350 \log (3+5 x)\\ \end{align*}

Mathematica [A]  time = 0.0175599, size = 57, normalized size = 1.04 \[ -\frac{505}{3 x+2}-\frac{275}{5 x+3}-\frac{34}{(3 x+2)^2}-\frac{7}{3 (3 x+2)^3}+3350 \log (3 x+2)-3350 \log (-3 (5 x+3)) \]

Antiderivative was successfully verified.

[In]

Integrate[(1 - 2*x)/((2 + 3*x)^4*(3 + 5*x)^2),x]

[Out]

-7/(3*(2 + 3*x)^3) - 34/(2 + 3*x)^2 - 505/(2 + 3*x) - 275/(3 + 5*x) + 3350*Log[2 + 3*x] - 3350*Log[-3*(3 + 5*x
)]

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Maple [A]  time = 0.008, size = 54, normalized size = 1. \begin{align*} -{\frac{7}{3\, \left ( 2+3\,x \right ) ^{3}}}-34\, \left ( 2+3\,x \right ) ^{-2}-505\, \left ( 2+3\,x \right ) ^{-1}-275\, \left ( 3+5\,x \right ) ^{-1}+3350\,\ln \left ( 2+3\,x \right ) -3350\,\ln \left ( 3+5\,x \right ) \end{align*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

int((1-2*x)/(2+3*x)^4/(3+5*x)^2,x)

[Out]

-7/3/(2+3*x)^3-34/(2+3*x)^2-505/(2+3*x)-275/(3+5*x)+3350*ln(2+3*x)-3350*ln(3+5*x)

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Maxima [A]  time = 1.09698, size = 76, normalized size = 1.38 \begin{align*} -\frac{90450 \, x^{3} + 177885 \, x^{2} + 116513 \, x + 25413}{3 \,{\left (135 \, x^{4} + 351 \, x^{3} + 342 \, x^{2} + 148 \, x + 24\right )}} - 3350 \, \log \left (5 \, x + 3\right ) + 3350 \, \log \left (3 \, x + 2\right ) \end{align*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate((1-2*x)/(2+3*x)^4/(3+5*x)^2,x, algorithm="maxima")

[Out]

-1/3*(90450*x^3 + 177885*x^2 + 116513*x + 25413)/(135*x^4 + 351*x^3 + 342*x^2 + 148*x + 24) - 3350*log(5*x + 3
) + 3350*log(3*x + 2)

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Fricas [A]  time = 1.49365, size = 298, normalized size = 5.42 \begin{align*} -\frac{90450 \, x^{3} + 177885 \, x^{2} + 10050 \,{\left (135 \, x^{4} + 351 \, x^{3} + 342 \, x^{2} + 148 \, x + 24\right )} \log \left (5 \, x + 3\right ) - 10050 \,{\left (135 \, x^{4} + 351 \, x^{3} + 342 \, x^{2} + 148 \, x + 24\right )} \log \left (3 \, x + 2\right ) + 116513 \, x + 25413}{3 \,{\left (135 \, x^{4} + 351 \, x^{3} + 342 \, x^{2} + 148 \, x + 24\right )}} \end{align*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate((1-2*x)/(2+3*x)^4/(3+5*x)^2,x, algorithm="fricas")

[Out]

-1/3*(90450*x^3 + 177885*x^2 + 10050*(135*x^4 + 351*x^3 + 342*x^2 + 148*x + 24)*log(5*x + 3) - 10050*(135*x^4
+ 351*x^3 + 342*x^2 + 148*x + 24)*log(3*x + 2) + 116513*x + 25413)/(135*x^4 + 351*x^3 + 342*x^2 + 148*x + 24)

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Sympy [A]  time = 0.161504, size = 51, normalized size = 0.93 \begin{align*} - \frac{90450 x^{3} + 177885 x^{2} + 116513 x + 25413}{405 x^{4} + 1053 x^{3} + 1026 x^{2} + 444 x + 72} - 3350 \log{\left (x + \frac{3}{5} \right )} + 3350 \log{\left (x + \frac{2}{3} \right )} \end{align*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate((1-2*x)/(2+3*x)**4/(3+5*x)**2,x)

[Out]

-(90450*x**3 + 177885*x**2 + 116513*x + 25413)/(405*x**4 + 1053*x**3 + 1026*x**2 + 444*x + 72) - 3350*log(x +
3/5) + 3350*log(x + 2/3)

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Giac [A]  time = 1.78946, size = 78, normalized size = 1.42 \begin{align*} -\frac{275}{5 \, x + 3} + \frac{225 \,{\left (\frac{339}{5 \, x + 3} + \frac{68}{{\left (5 \, x + 3\right )}^{2}} + 440\right )}}{{\left (\frac{1}{5 \, x + 3} + 3\right )}^{3}} + 3350 \, \log \left ({\left | -\frac{1}{5 \, x + 3} - 3 \right |}\right ) \end{align*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate((1-2*x)/(2+3*x)^4/(3+5*x)^2,x, algorithm="giac")

[Out]

-275/(5*x + 3) + 225*(339/(5*x + 3) + 68/(5*x + 3)^2 + 440)/(1/(5*x + 3) + 3)^3 + 3350*log(abs(-1/(5*x + 3) -
3))